What volume of O2 (g) and hydrogen (g) at STP are produced when 7.0 A of current is passed through a dilute aqueous solution of H2SO4 for 45 minutes?
Electrode equations:
(-) cathode 2H+ + 2 e- ==> H2or 4H+ + 4e- ==> 2H2 for molar electron comparison
(+) anode 4OH- -2e- ==> 2H2O(l) + O2
Quantity of electricity in Coulombs = current in A x time in seconds
Q = I x t = 7 x 45 x 60 = 18900 C, now 1 mole of electrons = 96500 C
so moles of electrons = 18900/ 96500 = 0.19585moles
it takes 4 moles of electrons to form 1 mole of oxygen gas
therefore moles of oxygen formed =0.19585 / 4 = 0.04896
1 mole of gas = 24000 cm3, therefore volume of gas = 0.04896x 24000 = 1175. 12cm3 of O2
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