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Consider the reaction: NO2(g) ® NO(g) + ½ O2(g). The data below were collected for the...

Consider the reaction: NO2(g) ® NO(g) + ½ O2(g). The data below were collected for the concentration of NO2 as a function of time.

a)Determined the average rate of the reaction between 10 and 20 s.

b)Determine the rate of appearance of O2(g) between 10.0 and 20.0 sec

Time (s)

0.0

10.0

20.0

30.0

40.0

50.0

[NO2] (M)

1.000

0.951

0.904

0.860

0.818

0.778
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Answer #1

(a) Average rate = - [A]/t = [A]final - [A]initial / tfinal - tinitial

(Here A is reactant and negative sign is to make quantity positive)

For the given reaction average rate = - [NO2]/t = -(0.904 - 0.951 / 20 - 10)= -(-0.047)/10 = 0.0047 M/s

(b) 1 mole of NO2 reacts to give 1/2 mole of oxygen

For the given reaction we can also write - 1/2[NO2]/t = [O2]/t

Thus average rate of formation of O2 = 0.0047/2 = 0.00235 M/s

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