What is the rate constant for a reaction based on the following experimental information?
Experiment | Rate (M/s) | [A] (M) | [B] (M) | [C] (M) |
1 | 1.444 | 0.27 | 0.75 | 0.8 |
2 | 1.444 | 0.459 | 0.75 | 0.8 |
3 | 1.4584 | 0.27 | 1.35 | 0.8 |
4 | 1.4584 | 0.459 | 0.75 | 3.28 |
First we have to write the rate equation = Rate = k[A]m[B]n[C]p
Let us find the order of the reaction then we can find Rate constant,k
From the table
Take (1) and (2) rows and plug in those values in the rate equation as shown below
here we cancel like terms
Here 1 can also be written as (1.7)0
m=0
Order with respect to [A] = 0
Now take rows (1) and (3) to find the order of [B]
here we cancel like terms
here 1.01 which is almost 1
n=0
Order of the reaction with respect to [B] = n= 0
Let us take rows (2) and (4)
here we cancel like terms
p=0
Order of the reaction with respect to [C] = p =0
Now let us find the rate constant, k by plugging the any row values into reate equation
Rate = k[A]m[B]n[C]p
Here i am taking first row values
1.444 = k[0.27]0[0.75]0[0.8]0
1.444 = k
Rate constant k = 1.444 M/s
Get Answers For Free
Most questions answered within 1 hours.