What is the rate constant for a reaction based on the following experimental information?
Experiment | Rate (M/s) | [A] (M) | [B] (M) | [C] (M) |
1 | 0.4416 | 0.6 | 0.58 | 0.54 |
2 | 1.9672 | 1.26 | 0.58 | 0.54 |
3 | 0.4549 | 0.6 | 1.856 | 0.54 |
4 | 5.857 | 1.26 | 0.58 | 1.674 |
Let the rate (r) be -r = K [A]m [B]n [C]p
m,n and p are orders w.r.t to A, B and C respectively. K is rate constant
From experiment 1, K[ 0.6]m [0.58]n [0.54]p = 0.4416 (1)
From experiment 2, K[ 1.26]m [0.58]n [0.54]p = 1.9672 (2)
Eq.2/ Eq.1 (1.26/0.6)m =1.9672/0.4416, m= 2
From experiment 3, K[ 0.6]m [1.856]n [0.54]p = 0.4549 (3)
Eq.3/ Eq.1 (1.856/0.58)n= 0.4549/0.4416= (3)n= 1 n =0
From experiment 4, K[ 1.26]m [0.58]n [1.674]p =5.857 (4)
Eq.4/ Eq.2 gives (1.674/0.54)p= 5.857/1.9672 p =1
The rate becomes -r = K[A]2 [C]
From Eq.1 0.4416= K[ 0.6]2 [0.54]
K =2.271 /M2.s
So the rate becomes –r = 2.271[A]2 [C]
Get Answers For Free
Most questions answered within 1 hours.