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A 45.80 mL aliquot from a 0.505 L solution that contains 0.495 g of MnSO4 (Fw...

A 45.80 mL aliquot from a 0.505 L solution that contains 0.495 g of MnSO4 (Fw = 151.00 g/mol) required 40.4 mL of an EDTA solution to reach the end point in a titration. What mass (in milligrams) of CaCO3 (FW = 100.09 g/mol) will react with 1.39 mL of the EDTA solution?

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