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How many mLs of methyl salicylate would be required to synthesize 25.0 g of salicylic acid?...

How many mLs of methyl salicylate would be required to synthesize 25.0 g of salicylic acid? The density of methyl salicylate is 1.174 g/mL.

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Answer #1

Methyl salicylate C6H4OH(COCH3) decomposes to give salicylic acid C6H4OH(COOH) and methanol (CH3OH)

C6H4OH(COCH3) → C6H4OH(COOH) + CH3OH

Molecular weight of salicylic acid =138.12 Moles of salicyclic acid =25/138.12=0.181 moles

From the stoichiometry of the reaction, 1 mole of salicylic acid is formed from 1 mole of methyl salicylate

0.181 moles of salicylic acid is formed from 0.181 moles of methyl salicylate

Molecular weigt of methyl salicylate= 152, mass of methyl salicylate =152*0.181=27.51 gm

densitt of methyl salicylate= 1.174 g/ml

Volume of methyl salicylate= mass/ density = 27.51/1.174=23.42 ml

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