Question

If you combine 440.0 mL of water at 25.00 °C and 140.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

Solution :-

When the hot water is mixed with cold water then hot water loses the heat and cold water absorbs it to attain the equilibrium temperature.

density of water is 1 g/ml so the mass of water is same as its volume

So we can make the following set up

- hot water = cold water

-140 g *(*T2-95.00 C) = 440.0 g * (T2-25.00 C)

-140 T2 + 13300 = 440 T2 - 11000

13300 + 11000 = 440 T2 + 140 T2

24300 = 580 T2

24300 / 580 = T2

41.89 C =T2

so the final temperature of the mixture is 41.89 ^oC