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A student pipetted 25.00 mL of a stock solution that was 0.1063 M HCl into a...

A student pipetted 25.00 mL of a stock solution that was 0.1063 M HCl into a 100.00 mL volumetric flask and diluted the solution to the volumetric flask calibration mark with deionized water. Calculate the concentration of the diluted solution.

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ANSWER.Given that 25 ml of 0.1063M HCl is pipetted into100 ml volumetric flask,so number of moles of both the solutions is same.let the number of moles in 25 ml of stock soltion=n1=M1V1 ----------(1) Let the number of moles in the diluted solution=n2=M2V2-------(2) M1=0.1063M ,V1=25 ml,V2=100ml, M2=? From(1) and (2) M1V1=M2V2 Substituting all the values in the above formula, 0.1063x25=100xM21

M2=2.66/100=0.0266M.

Concentration of diluted solution is 0.0266 M.

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