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The rate constant for a certain reaction is k = 7.30×10−3 s−1 . If the initial...

The rate constant for a certain reaction is k = 7.30×10−3 s−1 . If the initial reactant concentration was 0.750 M, what will the concentration be after 16.0 minutes?

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Answer #1

given that, rate constant (K) = 7.30 10-3 s-1

units is s-1, so it is first order reaction.

Initial concentration (N0) = 0.750 M

time (t) = 16.0 minutes = 16 60 sec = 960 sec.

after 16 minutes concentration of reactants (N) = ?

for first order reaction,K = ( 2.303 / t ) log ( N0 / N )

7.30 10-3 = ( 2.303 / 960 ) log ( 0.750 / N )

log ( 0.750 / N ) = ( 7.30 10-3 960 ) / 2.303

log ( 0.750 ) - log ( N) = 7.008 / 2.303

-0.1249 - log N = 3.0429

log N = - 0.1249 - 3.0429

log N = - 3.1679

N = 10-3.1679

N = 0.00068 M.

Concentration after 16 minutes is ( N ) = 0.00068 M.

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