1)
Given:
lambda = 5.05*10^-7 m
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(5.05*10^-7 m)
= 3.936*10^-19 J
This is energy of 1 photon
Answer: 3.94*10^-19 J
2)
Now find the energy of 1 mol of photon.
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 3.936*10^-19*6.022*10^23 J/mol
= 2.37*10^5 J/mol
= 2.37*10^2 KJ/mol
So,
Energy of 5.00 mol = number of mol * Energy of 1 mol
= 5.00 mol * 2.37*10^2 KJ/mol
= 1.18*10^3 KJ
= 1.18*10^6 J
Answer: 1.18*10^6 J
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