Question

Explain why the steel cooled in air becomes ductile and the steel quenched in water becomes...

Explain why the steel cooled in air becomes ductile and the steel quenched in water becomes brittle

Homework Answers

Answer #1

The fast cooling process is otherwise known as quanching. quenching results in a metal that is very hard but also brittle. quenching of metal can reduce the crystal grain size of metallic materials, so it will case the increase of hardness. Gently heating a hardened metal and allowing it to cool slowly will produce a metal that is still hard but also less brittle. This process is known as tempering. It results in many small Fe3C precipitates in the steel, which block dislocation motion which thereby provide the strengthening.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
why is the air-cooled and furnace cooled specimens can be cooled in water after 60 minutes?
why is the air-cooled and furnace cooled specimens can be cooled in water after 60 minutes?
Explain why BCC metals undergo a brittle to ductile transition and fcc metals do not in...
Explain why BCC metals undergo a brittle to ductile transition and fcc metals do not in terms of dislocations and the metals' crystal structures ? Please explain in a good words!!! Thanks
Please use the characteristics of chemical bonding, crystal structures and dislocations to explain why metallic materials...
Please use the characteristics of chemical bonding, crystal structures and dislocations to explain why metallic materials are strong and ductile and why ionic and covalent materials are strong but brittle?
Question 3 (5 marks) Air at 150 kPa, containing 1 % water (mass basis), is cooled...
Question 3 Air at 150 kPa, containing 1 % water (mass basis), is cooled to its dew point. Without using a psychrometric chart, determine the air’s absolute humidity and dew point. MW)air = 29 g/mol ; MW)water = 18 g/mol
Question 5 (a)(i) What theories of failure are used for? Ductile of materials and Brittle of...
Question 5 (a)(i) What theories of failure are used for? Ductile of materials and Brittle of materials? (2marks) (ii) List at least two factors that promote the transition from ductile to brittle fracture? (2marks) (iii) Often, it is beneficial to know how many materials or components can be combined without producing an additional phase. When alloying elements are added to metal, solid or liquid solutions can be formed. For example, when we add sugar to water, sugar solution is obtained....
1. The following data were obtained from a Charpy impact test for a ductile cast iron...
1. The following data were obtained from a Charpy impact test for a ductile cast iron containing 2.55 wt% Si. Plot the data and find the ductile to brittle transition temperature. What does this transition temperature signify? Would you use this material in a product that undergoes constant impact forces below 0oC? Why or why not? Explain. Use graph supplied on next page. TEST TEMPERATURE (oC) IMPACT ENERGY (ft-lb) -50 4 -20 4 0 6.4 8 8.8 14 12 20...
material Science 3. using the concept of the relation between glass transition temperature and structure, explain...
material Science 3. using the concept of the relation between glass transition temperature and structure, explain why polyethylene is ductile at room temperature whereas polystyrene is brittle at room temperature.
Consider a plain carbon steel (0.65 wt% carbon) that was successfully water quenched and then tempered...
Consider a plain carbon steel (0.65 wt% carbon) that was successfully water quenched and then tempered at 400 degrees C for 1 hour. Determine the identity of the phases and the phase fractions expected after tempering. If the tempering temperature is decreased to 300 degrees celsius but the tempering time is kept constant, what would the effect on the proportion of phases present and the yield strength?
Problem #2 Air at 80°F and 80% relative humidity are cooled to 51°F at a constant...
Problem #2 Air at 80°F and 80% relative humidity are cooled to 51°F at a constant pressure of 1 atm. Use the psychrometric chart to calculate the fraction of water that condenses, and the rate at which heat must be removed to deliver 1,000 ft3 /min of humid air at the final conditions.
A closed container of air and water vapor is at 95 degrees Celsius and 5000 mm...
A closed container of air and water vapor is at 95 degrees Celsius and 5000 mm Hg and contains 12% water by volume. Antoine constants for water are A=7.97, B=1668.2, C=228.0. a) Calculate the dew point temperature and degrees of superheat of the air-water mixture. b) If the air-water mixture is cooled isobarically to a point where the mole fraction of air is .915, what is the temperature and percentage of the water vapor that condenses?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT