1.) The decomposition of phosphine (PH3) is a 1st order reaction.
A.) If the half life of the reaction is 35.0s, what is the rate constant?
B.) How long will it take for 75% of the phosphine to decompose?
for first order reaction rate and concentration are related as - dc/dt= kc (1)
where K= rate constant and c= concentratino at any time
Eq.1 upon integration gives -ln (1-XA)= kt (2) where XA= 1-CA/CAO
CA= cocentration at any time t and CAO= initital concentratin
for half lfe, the cocentratino CA should drop down to 50% of its inital value CA=0.5CAO and XA=0.5
from Eq.2 -ln (1-0.5)= k*35
k= 0.693/35 sec-1=0.0198 sec-1
b) for 75% conversion , i.e XA=0.75 and from eq.2 -ln (1-0.75)= 0.0198*t
t= time taken
t= 1.386/0.0198 =70 sec
Get Answers For Free
Most questions answered within 1 hours.