Question

A) what is the frequecny of electromagnetic radiation that has a wave length of 610pm?

B) the visible portion of the electromagnetic spectrum covers the range from appro. 350 to 700nm. Is the electromagnetic radiation descrided in part A visible to the eye?

C) How far woulf the electromagnetic radiation descrided in part A travel in 1.0 second?

I would like to know how to solve each of these questions

Answer 1

Ans :

A)

wavelength = 610 pm = 610 x 10^-12 m

Frequency = speed of light / wavelength

= (3.0 x 10⁸) / (610 x 10^-12)

= 4.92 x 10¹⁷ Hz

B)

Yes the visible portion of electromagnetic spectrum that lies in the range from 350 nm to 700 nm is visible to eye. This is the kind of radiation that we refer to as light.

C)

The speed of light is 3.0 x 10⁸ m/s

So the distance that electromagnetic radiation travels in 1.0 second will be :

= 3.0 x 10⁸ x 1.0

= 3.0 x 10⁸ meters