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I have listed two questions. Correct answers are greatly appreciated. A) How many moles of hydroxide...

I have listed two questions. Correct answers are greatly appreciated.

A) How many moles of hydroxide ions are present in 75.9 mL of 1.4 M calcium hydroxide? Enter to 4 decimal places.

B) Complete the following acid-base reactions with balanced molecular, total ionic, and net ionic equations: Barium hydroxide + hydrofluoric acid

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Homework Answers

Answer #1

1. The no. of moles of calcium hydroxide = 75.9*10-3 L * 1.4 M, i.e. 106.26 mol

The dissociation of Ca(OH)2 in water can be written as shown below.

Ca(OH)2(aq) Ca2+(aq) + 2OH-(aq)

Therefore, the no. of moles of hydroxide = 2*106.26, i.e. 212.52 mol = 0.2125 mmol

2. Balanced molecular equation: Ba(OH)2(aq) + 2HF(aq) BaF2(s) + 2H2O(l)

Total ionic equation:​ Ba2+(aq)​ + 2OH-(aq)​ + 2H+(aq)​ + 2F-(aq)​ BaF2(s)​ + 2H+(aq)​ + 2OH-(aq)​

Net ionic equation:​ Ba2+(aq)​ + 2F-(aq)​ BaF2(s)​

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