Question

If you combine 430.0 mL of water at 25.00 °C and 130.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

Solution :-

hot water = 130.0 ml at 95.00 C

cold water = 430.0 ml at 25.00 C

density of water is 1 g/ml so 430.00 ml = 430 g and 130.00 ml = 130 g

final temperature of water after mixing = ?

hot water loses heat to cold water

so we can make the following set up

- q hot = q cold

-m*delta T = m*delta T

- 130.0 g * (T2- 95.00 C) = 430.0 g * (T2-25.00 c)

-130 T2 + 12350 = 430 T2 - 10750

12350 + 10750 = 430 T2 + 130.0 T2

23100 = 560 T2

23100 / 560 = T2

41.25 C =T2

So the final temperature of the mixture is 41.25 ^oC