The work function of silicon is 7.24 × 10–19 J. Calculate the velocity of the emitted electron if the surface is irradiated with UV radiation of wavelength 240 nm. If lower velocity electrons were required, should a material with higher or lower work function be used? Explain.
Eo = 7.24*10^-19 J
lets calculate the energy of wavelength
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2.4*10^-7 m)
= 8.28*10^-19 J
KE of electron = E - Eo
= 8.28*10^-19 J - 7.24*10^-19 J
= 1.04*10^-19 J
mass of electron, m = 9.11*10^-31 kg
Use:
KE = 0.5*m*v^2
1.04*10^-19 = 0.5*9.11*10^-31*v^2
v = 4.78*10^5 m/s
Answer: 4.78*10^5 m/s
for electron to have lower velocity (means kinetic energy of electrons should be less), Eo should be more
So, material with higher work function be used
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