Question

Consider the reaction: A(g)+1/2B(g)→2C(g). Determine the expression for the rate of the reaction with respect to each of the reactants and products. When C is increasing at a rate of 1.5×10−2 M⋅s−1 , how fast is B decreasing?How fast is A decreasing? please show work, i am a but lost

Answer 1

Answer – We are given the reaction –

A(g)+ ½ B(g) -----> 2C(g)

Rate of C increased, ∆[C] /∆t = 1.5*10^-2 M.s^-1

Rate of B decreasing –

We know

Rate = - ∆[A] /∆t = -2* ∆[B] /∆t = ½ ∆[C] /∆t

So, ∆[B] /∆t = 1/2*2 * ∆[C] /∆t

                     = ¼ * 1.5*10^-2 M.s^-1

                     = 3.75*10^-3 M.s^-1.

Rate of A decreasing –

We know

Rate = - ∆[A] /∆t = -2* ∆[B] /∆t = ½ ∆[C] /∆t

So, ∆[A] /∆t = ½ * ∆[C] /∆t

                     = ½ * 1.5*10^-2 M.s^-1

                     = 7.5*10^-3 M.s^-1.