Question

shielding constant of elements V, Mn, Fe.

shielding constant of elements V, Mn, Fe.

Homework Answers

Answer #1

: Other electrons within same group shield 0.35 and electrons within the lower group shield 1.00

  1. Vanadium(V): Ground state electronic configuration of V(At.No.= 23) is 1s2,2s2 ,2p6 ,3s2 ,3p6,3d3 ,4s2 ( 2 electrons within group and 18 electron within lower group)

So, Screening constant(S) for valence electron in V = (2x0.35) + (18x1.00) = 18.70

  1. Manganese (Mn): G.S.E.C of Mn (At.No. =25) is 1s2,2s2 ,2p6 ,3s2 ,3p6 ,3d5 ,4s2 (4 ele. within group and 18 within lower group)

So, S (Mn) = 4x0.35 + 18x1.00 = 19.40.

  1. Iron (Fe): G.S.E.C.(At.No. 26) is 1s2,2s2 ,2p6 ,3s2 ,3p6 ,3d6 ,4s2 (5 ele. within group and 18 in lower group)

So, S (Fe) = 5x0.35 + 18x1.00 = 19.75

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