Question

a 100 gram sample of nacl is added to 100 ml of water at 0 degrees Celsius. after equilibrium is reached, about 64 g of solid remains I dissolved. describe the equilibrium that exists in this system at the particulat

Answer 1

molarity = weight of NaCl*1000/G.M.Wt of NaCl *volume of solution in ml

            = 100*1000/58.5*100

           =17.09 M

molarity = 64*1000/58.5*100

                  NaCl <----> NaCl

initial conc 17.09M       0

change        10.94M        10.94M

remains conc 6.15 M         10.94   at equlibrium