Question

What gas is produced when a calcium carbonate (tums) tablet is dropped into a solution of HCl? Show the chemical reaction. How many moles of that gas should be produced if there is 500 mg of calcium carbonate?

Answer 1

CaCO3(s) + 2HCl(aq) ...........> CaCl2(aq) + CO2(g) + H2O(l)

CO2 gas releases

To calculate no. of moles of CO2 we have to calculate no. of moles of CaCO3

no. of moles of CaCO3 = weight/moleculer weight

                                 = 0.5gm/100 = 0.005 moles

As per the above balanced eq.

1 mole of CaCO3 can give 1 mole of CO2

0.005 moles of CaCO3 ..........................?

            0.005*1/1 = 0.005 moles of CO2 gas can produce