Question

it's a lab work! aim is to determine the mass of CO2 given off in the reaction NaHCO3+HCl gives NaCl+H2O+CO2. i have 2.046 g of NaHCO3 and from that i got the theorotical mass of CO2 (1.07).Mss of HCL is 50.014. i need help in finding the experimental yield, % yield and error %. Is there any way to get the answer without doing the experiment. i would loose 50 points if i don't turn this in by tomorrow. help me please. Any help would be greatly appreciated

Answer 1

NaHCO₃+HCl-----> NaCl+H2O+CO₂

Theoretical yeild = 1.07. It means 2.046g Of NaHCO₃ will give 1.07g of CO₂. If we get 1.07g of CO₂ by experiment the experimental yield is 100%. (The amount that we actualy get from experiment is called experimental yield.) However it is not possible to get 100% yeild. That means we will always get less than 1.07g of CO2 from 2.046g of NaHCO₃ .

% Experimental yeild = (Amount of CO₂ that we get in experiment / 1.07) X 100

You have to perform experiment to get amount of CO₂ produced by the reaction And REMEMBER amount of CO₂ will always be less than 1.07g. Than use above equation to calculate % yield.

% error = {(1.07 - Amount of CO2 produced in experiment) / 1.07} X 100