Question

The density of a 1.22 M aqueous sucrose soluton (C₁₂H₂₂O₁₁) is 1.25 g/mL. Calculate the molal concentration, mole fraction (sucrose) and the mass percent (sucrose) of the solution. What volume (mL) of the solution would contain 100 g of sucrose?

Answer 1

Answer; According to the question

Here we have density = 1.25 g/ml means = 1250 gram /L

generally density = mass / volume

Here we have given the 1.22 M aq solution means 1 L solution conatins 1.22 moles

moles = mass / molar mass

Molar mass is = 342.29

Hence Mass = 1.22 * 342.29 gram = 417.5938 gram

Now using density formula to calculate the volume

1250 g/l = 417.5938 / Volume in L

Volume = 0.33407 L = 334.07 ml

Now according to question ,

Here 334.07 Ml contains = 417.6 g of Sucrose solution

Hence 100 g solution contains = 334.07 * 100 / 417.6 ml 79.99 ml

Hecne the required answer is 79.99 ml .

Thank you :)