Question

Methane gas (CH₄) reacts with chlorine gas (Cl₂) to produce liquid carbon tetrachloride (CCl₄) and hydrogen chloride gas(HCl). The balanced chemical equation for the reaction is as follows:

CH₄(g) + 4 Cl₂(g) → CCl₄(l) + 4 HCl(g).

Calculate the number and types of atoms present in the reactants in this chemical equation.

C

Cl

H

Answer 1

>>>>>in reactant there is 1 mole of CH4 and contains 1 mole of C and 4 mole of H

1 mole of C = 1 6.022 10²³ = 6.022 10²³ atom

4 mole of H = 4  6.022 10²³ = 2.4088 10²⁴ atom

>>>>>in reactant there is 4 mole of Cl₂ and each molecules contain 2 Cl

so total mole of Cl = 8 mol

8 mol of Cl = 8   6.022 10²³ = 4.8176 10²⁴ atom.

so, finally

atoms of C = 6.022 10²³ atom

H = 2.4088 10²⁴ atom

Cl =  4.8176 10²⁴ atom.