How does valence relate to the type of bond an atom can make?
Atoms form the number of bonds in order to complete their octet and reach the closest stable inert gas configuration, the number of valence electrons determine the behavior of bond formation
Ex - Na(11) = 1s2 2s2 2p6 3s1 just need to lose one electron to reach the noble gas configuration whereas it has to attain 7e- to reach the Ar
Hence the group 1,2 generally tend to loose electrons equal to the number of valence electrons whereas electronegative element like O and F, tend to gain 1 or 2 electrons in order to complete their octet
In their case, number of bonds = 8 - (number of valence electrons)
Ex - F = 1s2 2s2 2p5, bonds formed = ( 8 - (2+5)) = 1
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