Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose 11. g of ethane is mixed with 56.4 g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.
2 C2H6 + 5 O2 -----------------------> 4 CO2 + 6 H2O
60 g 160 g
11.0 g 56.4 g
60g C2H6 ------------------> 160 g O2
x g C2H6 --------------------> 56.4 g O2
x = 60 x 56.4 / 160
x = 21.15 g
actually 21.15 g ethane needed for 56.4 g O2
but we have only 11.0 g ethane . so total ethane will be consumed
mass of ethane left = 0.0 g
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