Question

An aqueous solution contains 4.3% NaCl by mass.

**Part A**

Calculate the molality of the solution.

Express your answer using two significant figures.

**Part B**

Calculate mole fraction of the solution.

Express your answer using two significant figures.

Answer #1

is 4.3 grams of NaCl / 100 total grams of mix

allowing us to say that's

4.3 grams of NaCl / 95.7 grams of H2O

use molar mass to find moles:

4.3 g NaCl divided by 58.44 g NaCl / mol = 0.07357 mol NaCl

A) Calculate the molality of the solution.

0.07357 mol NaCl / 0.0957 kg of H2O = 0.7688 molal

95.7 grams of H2O

use molar mass to find moles:

95.7 grams of H2O divided by 18.01 g H2O / mol = 5.31 mol H2O

total moles = 5.31 mol H2O + 0.07357 mol NaCl = 5.387 total
moles

B) Calculate mole fraction of the solution

0.07357 mol NaCl / 5.387 total moles = 0.01365 mole fraction
NaCl

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