Write formulas for the following molecules using elemental symbols from the periodic table and subscripts. a.) A molecule of aluminum chloride, in which the ratio of aluminum atoms to chlorine atoms is 1 to 3. b.) A molecule of carbon dioxide.
a) The atomic number of Al is 13, and the electronic configuration is 1s22s22p63s23p1. The outermost shell has 3 electrons. By losing 3 electrons Al atom converts to Al3+ ion (because Al is metal).
The symbol for chlorine atom is: Cl
The atomic number of Cl is 17, and the electronic configuration is 1s22s22p63s23p5. The outermost shell needs one electron to get stable configuration. By gaining 1 electron Cl atom converts to Cl- ion (Cl is non-metal).
By Criss-Cross method we get the formula of Aluminium chloride.
The metal is written first. The nonmetal is written second. Criss-cross the charges from the metal and nonmetal. Finally we will have the molecular formula AlCl3 given below.
b) Carbon dioxide molecule contains one carbon atom with symbol C and two oxygen atoms (oxygen atom symbol is O). Therefore the molecular formula is CO2.
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