Question

For this problem, I need to create a step by step process in order to determine all of these things in a lab. I understand how to create the 50 ml of each concentration by calculating mols from mol= MV, and then adding water.

What I do not understand is how to isolate the product and turn it in to an anhydrous salt. (Maybe vaccum filtration?)

I also need to be able to find the concentration from the supernatant.

Create exactly 50.0 mL of aqueous 0.500 M CuSO4 solution from solid CuSO4*5H2O, and be sure that the crystals are dissolved. Create exactly 50.0 mL of aqueous 0.300 M Ca(NO3)2*4H20 and mix it with the previous solution. Let it react for 20 minutes. Isolate the hydrate product, and then generate an anhydrous salt. Then find the concentration of the supernatant. a Calibration curve will be provided if needed.

Answer 1

M1V1 = M2V2

number of moles of solid CuSO4*5H2O = 0.05L x 0.5 M = 0.025 moles

mass of solid CuSO4*5H2O = 249.72 g/mol x 0.025 moles = 6.243 g

6.243 g of CuSO4*5H2O dissolved in 50.0 ml water then solution will be 0.500 M and 50.0 ml

similarly for 50.0 ml of 0.30M CuSO4*5H2O

number of moles of solid CuSO4*5H2O = 0.05L x 0.3 M = 0.015 moles

mass of solid CuSO4*5H2O = 249.72 g/mol x 0.015 moles = 3.7458 g of CuSO4*5H2O dissolve in 50.0 ml water

after 20 min.

M1V1 + M2V2 = M3V3

after rection total volume will be 100.0ml

M3 = ( M1V1 + M2V2 / V3 ) = 0.4 M