Question

A sample of a gas has a volume of 38.12 mL and a temperature of 28.15°C. If the gas is heated to a temperature of 85.20°C, what would be the final volume of the gas in milliliters?

Answer 1

We will use Charles law to solve this question

According to Charles law

V₁ / T₁ = V₂ / T₂

where ,

V₁ = initial volume of the gas = 38.12 milliliter

V₂ = final volume of the gas = To be found out

T₁ = initial temperature of the gas = 28.15°c

= 28.15 + 273 = 301.15k

T₂ = final temperature of the gas = 85.20°c

= 85.20 + 273 = 358.2 k

( to convert °c to Kelvin just add 273 to temperature given in °c)

Now substitute all values in the equation

V₁/T₁ = V₂/T₂

38.12 / 301.15 = V₂ / 358.2

0.1265 = V₂ / 358.2

0.1265 * 358.2 = V₂

45.31 milliliter = V₂

Hence the final volume of gas is 45.31 milliliter