Question

What is the mole percent of the solution prepared by mixing 17.2g of C2H6O2 with .500 kg of H2O to make 515 mL of solution?

(18 g/mol for H2O, for C2H6O2 mol/ 62.02)

Answer 1

moles of water = 500/18 = 27.78

moles of C2H6O2 = 17.2/ 62.02 = 0.277

X solute = (moles of solute)/(moles of solute + moles of solvent)

             = (0.277) / 28.057

             = 0.00987

mole percent = 0.00987 *100

                    = 0.987%