A 4.6-L sealed bottle containing 0.39 g of liquid ethanol, C2H6O, is placed in a refrigerator and reaches equilibrium with its vapor at −11°C. The vapor pressure of ethanol is 10. torr at −2.3°C and 40. torr at 19°C.(c) How much liquid ethanol would be present at 0.0°C?
First we have to calculate the enthalpy of vaporization
Vapor pressure at -2.3 oC = P1 =10 torr
Vapor pressure at 19 oC = P2 = 40 torr
Initial temperature = T1 = -2.3 oC = 270.85 K
Final temperature = T2 = 19 oC = 292.15 K
R = 8.314 J/K.mol
Using Clausius-Clapeyron equation
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