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A reaction vessel at 1215 K contains a mixture of SO2(P= 2.90 bar ) and O2(P=...

A reaction vessel at 1215 K contains a mixture of SO2(P= 2.90 bar ) and O2(P= 1.20 bar ). When a catalyst is added the reaction 2SO2(g)+O2(g)⇌2SO3(g) takes place. At equilibrium the total pressure is 3.85 bar . Find the value of K.

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Answer #1

2SO2(g) +   O2(g) -----------------> 2SO3(g)

2.90              1.20                                0

2.90 - 2x        1.20 - x                           2x

at equilibrium the total pressure = 3.85 bar

2.90 - 2x + 1.20 - x +    2x = 3.85

x = 0.25

PSO2 = 2.90 - 2x = 2.90 - 2 x 0.25 = 2.40 bar

PO2 = 1.20 - x = 1.20 - 0.25 = 0.95 bar

PSO3 = 2x = 2 x 0.25 = 0.5 bar

Kp = P2SO3 / P2SO2 x PO2

      = 0.5^2 / 2.4^2 x 0.95

Kp    = 0.0457

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