1. Which would you expect to have a larger Rf value by TLC: the starting material, 9- fluorenol, or the product of this reaction 9-fluorenone?
2. For the reaction you are about to run, what is the oxidant and what is the reductant?
1) In the reaction oxidation to 9-fluorenol to 9-fluorenone, the 9-fluorenol is alcohol. Hence it has more affinity towards polar silica as the stationary phase in TLC. Thus it will not move fast as compared to product ketone. Thus Rf value of the product 9-fluorenone will be larger than the starting material 9-fluorenol.
2) As the information on the reaction you are carrying out is not given it may not be possible to answer this question. However,
often in the experiments, we use either NaOCl + acid or K2CrO4 or K2Cr2O7 as an oxidizing reagent. And the reductant is the alcohol, 9-fluorenol.
Please let me know your reaction reagents and conditions used in your experiment in the comment section. Accordingly, I will update my answer to the second question.
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