Question

In one meteorite the activity of Mn-53 was determined to be 50.0 dpm in exactly 1.0kg...

In one meteorite the activity of Mn-53 was determined to be 50.0 dpm in exactly 1.0kg of of meteorite. Calculate the number of MN-53 atoms there would be in a 1.0g sample of this meteorite.

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Answer #1

We know rate of nuclear reactions follows first order kinetics. We can look up for half life of Mn-53 in order to get rate decay constant. Once we get decay constant we can get number of atoms there by using given activity (decay rate ). We have to find number of atoms in 1.0 g and that can be done by using number of atoms in 1.0 kg.

Half life of Mn-53 is 3.74 E6 years. We use this in minute since we are given rate in dpm. This means that disintegration per minute.


So the number of Mn-53 atoms in 1.0 g = 1.38 E12 atoms

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