Question

Four ice cubes at exactly 0 ∘C with a total mass of 55.0 g are combined with 130 g of water at 80 ∘C in an insulated container. (ΔH∘fus=6.02 kJ/mol, cwater=4.18J/g⋅∘C) If no heat is lost to the surroundings, what is the final temperature of the mixture

Answer 1

Q = m Hf

    = (55/18) x 6.02

    = 18.4 kJ

    = 18400 J

combined with 130 g of water

Q = 130 x 4.18 x (80)

    = 43472 J

left over energy = 43472 - 18400

                          = 25072 J

25072 = 185 x 4.18 x (Tf - 0)

Tf = 32.4∘C

final temperature of the mixture = 32.4∘C