Question

Ammonia gas can be prepared by the reaction:

CaO (s) + 2 NH₄Cl (s) → 2 NH₃ (g) + H₂O (g) + CaCl₂ (s)

If 672 g of calcium oxide is mixed with excess ammonium chloride and allowed to react and the percent yield is 95.6%, what mass of ammonia is produced?

Answer 1

Ammonia gas can be prepared by the reaction:

CaO (s) + 2 NH₄Cl (s) ---- > 2 NH₃ (g) + H₂O (g) + CaCl₂ (s)

If 672 g of calcium oxide is mixed with excess ammonium chloride and allowed to react and the percent yield is 95.6%, what mass of ammonia is produced?

Solution :-

Using the mole ratio of the CaO and NH3 we can calculate the mass of NH3 that can be produced

(672 g CaO* 1 mol / 56.078 g) *(2 mol NH3/1 mol CaO)*(17.03 g / 1 mol NH3)*(95.6 % /100%) = 390 g NH3

So the mass of NH3 that can be formed = 390 g NH3