Question

Show that a plot of ln(time) vs1/Temp. should give a straight line with a slope of...

Show that a plot of ln(time) vs1/Temp. should give a straight line with a slope of Ea/R.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

According to the arrhenius equation

Taking log both sides we get

The concentration K is dependent on time, hence the equation can be written in the form of

where y = ln(time), x = 1/T, then m=-Ea/R and constant equal to ln(A)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
It we plot logarithm of the potential difference (ln(V)) on the capacitors versus time, then the...
It we plot logarithm of the potential difference (ln(V)) on the capacitors versus time, then the slope of the best fit line would be equal to -1/RC. True? False?
How do I plot an appropriately labelled graph of ln (T∞ - Tt)against time (t) and...
How do I plot an appropriately labelled graph of ln (T∞ - Tt)against time (t) and calculate the rate constant (k) from the slope (gradient) using a line of best fit? I want the graph drawn by hand. The ln(A)0 are ( 2.31,2.16,2.09,2.37,2.34,2.06,2.09,2.09,2.09) and the time (10,20.5,30,40.1,50.27,60,70,80,90) 10 20.5 30 40.1 50.27 60 70 80 90 2.31 2.16 2.09 2.37 2.34 2.06 2.09 2.09 2.09
would the slope of a ln(k) versus 1/T (K) plot for a catalyzed reaction be more...
would the slope of a ln(k) versus 1/T (K) plot for a catalyzed reaction be more or less negative than the slope of the ln(k) versus 1/T (K) for the uncatalyzed reaction? Explain. Assume both rate laws for the ccatalyze and uncatalyzed reaction are all first- order overall.
An Arrhenius plot (ln k vs. 1/T) for a second order reaction (2A -> C) produced...
An Arrhenius plot (ln k vs. 1/T) for a second order reaction (2A -> C) produced a straight line with a slope of -8.23e+03 K. What is the value of the Arrhenius pre-exponential if k = 4500 M-1 s-1 at 690 K?
Suppose that you follow a population over time. When you plot your data on a semilog...
Suppose that you follow a population over time. When you plot your data on a semilog plot (using logs with base 10), a straight line with slope 0.21 results. Furthermore, assume that the population size at time 0 was 50. What function best describes the population size at time t? Population at time t is ________________ (simplify as much as you can, there should be no logs in answer)
Table V – Sample 2, Half-life Determination using Natural Log Decay Plot Note: Slope Method is...
Table V – Sample 2, Half-life Determination using Natural Log Decay Plot Note: Slope Method is used here (see "Summary of Formulas and Concepts Needed for Calculations" under Background tab) Trial Probe Distance (cm) Ln( Rate ) when T = 8.00 s Ln( Rate ) when T = 32.0 s Slope of Line Half-life 1 20 8.38 7.89 2 25 8.82 8.33 Sample Calculation: For Trial 2, show your slope of line calculation. Sample Calculation: For Trial 2, show your...
Show in details how we can mathematically modify the two equations below to get a straight-line...
Show in details how we can mathematically modify the two equations below to get a straight-line graph from each of these equations. Compare the 2 new equations to the general equation of s straight line and show what the slope (m) represents. How can we calculate the value of capacity from the slope of the line? Equation 1: V = V0e-t/RC Equation 2: V = V0(1 - e-t/RC)
The kinetics of the reaction A + 3B → C + 2D were studied and the...
The kinetics of the reaction A + 3B → C + 2D were studied and the following results obtained, where the rate law is: – = k[A]n[B]m For a run where [A]0 = 1.0 × 10–3 M and [B]0 = 5.0 M, a plot of ln [A] versus t was found to give a straight line with slope = –5.0 × 10–2 s–1. For a run where [A]0 = 1.0 × 10–3 M and [B]0 = 10.0 M, a plot...
In a decomposition reaction N₂O₅ --> products, a plot of the on [N₂O₅] vs time yields...
In a decomposition reaction N₂O₅ --> products, a plot of the on [N₂O₅] vs time yields a straight line with a slope of -0.0363/s. If the initial concentration of [N₂O₅] is 4.0 M, what is the concentration after 155 seconds? What is the half-life of the reaction?
How to determine what to plot in order to get a straight line relationship and also...
How to determine what to plot in order to get a straight line relationship and also what further information can be derived from the graph.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT