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A Steel (p=7820kg/m^3) cylinder has a volume of .2L and holds 3kg of water at 25...

A Steel (p=7820kg/m^3) cylinder has a volume of .2L and holds 3kg of water at 25 degrees C and 200 kPa (p=997 kg/m^3).

A) Finf the total mass and total volume of the system (cylinder+water)

B) Give the values for two extensive properties and two intensive properties of the water.

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Answer #1

A)

density of water = 997 kg/m^3 = 0.997 gm/cm^3

Volume of water = Mass/density = 3000/0.997 = 3009.02cm^3 = 3.0092L

Total volume = volume of water + volume of steel = 0.2L + 3.0092 = 3.2092 L

Mass of steel = Density * VOlume = 7.820 gm/cm^3 * 200 = 1564 gms = 1.564 Kg

Mass of system = mass of water + mass of steel = 4.564 Kg

B)

Extensive Properties are Mass and Volume, which will vary from experiement to experiment

Mass of water = 3 Kg

Volume of water = 3.0092 L

Intensive Properties are density and temperature, which is intensive i.e. 25C for this reaction and 997 Kg/m^3

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