Question

A 10 wt% aqueous sulfuric acid solution (ρ = 1.066 g/mL) flows through a 75 m long pipe with a 4 cm diameter at a rate of 94 L/min.

a) What is the molarity of sulfuric acid in the solution?

b) How long (in seconds) would it take to fill a 55-gallon drum, and how much sulfuric acid (lb_m) would the drum contain? (You should arrive at your answers with two, dimensional equations.)

c)

Answer 1

a) Let us consider 1 kg solution = 1000 g

Volume of solution = mass/density = 1000 / 1.066 = 938 ml = 0.938 L

for 1 kg solution sulphuric acid present = ( 10/100) x 1 = 0.1 kg = 100 g

sulphuric acid moles = mass/molar mass = 100 / 98.079 = 1.0196

Molarity = moles of H2SO4 / solution vol in L = 1.0196 /0.938 = 1.087 M

b) 55 galons = 55 x 3.78541 = 208.19755 L

Rate of slow = 94 L /min

we need 208.19755 L

Hence time = Volume / rate = 208.19755 /94 = 2.21486 min

Time in s = 60 x time in min = 2.24186 x 60 =132.9 s = 133 s