Question

The decomposition of NO2 2NO2(g) → 2NO(g) + O2(g) is second-order in NO2. Given that the...

The decomposition of NO2

2NO2(g) → 2NO(g) + O2(g)

is second-order in NO2. Given that the half-life for the inital concentration of NO2 equal to 0.848 M is 221 s, find the concentration of NO2 after 663 s.

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Answer #1

The relationship between half life and initial concentration is given below

   t 1/2 = 1 / K (A0)

221 = 1 / K ( 0.848)

K = 1 / 221(0.848)

K = 0.0053 M- s-

Now in order to find the concentration of NO2

   1 / (At)   - 1 / (A0) = Kt

             1 /( At) = Kt + 1 /( Ao)

             1 / (At) = 0.0053(663) + 1 / 0.848

              1 /( At) = 4.71

                ( A t ) = 0.212M    Answer

        This will be the concentration after 663 sec

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