Calculate the solubility (in g / L) of a generic salt with a
formula of A2 B, a Ksp of 3.60 × 10^−12 and a molar mass of 106 g /
mol.
A2B -----------> 2A+ + B2-
2S S
Ksp = [A+]^2[B2-]
3.60 x 10^-12 = (2S)^2 x S
4S^3 = 3.60 x 10^-12
S = 9.65 x 10^-5 M
solubility = 9.65 x 10^-5 mol / L
= 9.65 x 10^-5 x 106
solubility = 0.0102 g / L
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