Question

Calculate the number of collisions per second of one hydrogen molecule at 25 °C and 6.00...

Calculate the number of collisions per second of one hydrogen molecule at 25 °C and 6.00 bar. The diameter of a hydrogen molecule is 270 pm.

Homework Answers

Answer #1

The no. of collisions suffered by a single gaseous molecule is give by the following equation

Z = 1.414 X π X d2 X <c> X P/kT

<c> = average velocity = (8RT/πM)1/2 = [8 X (8.314J/Kmol) X (298K) / 3.1416 X 2 X 10-3Kg/mol) = 1776.3ms-1

d = diamter = 270 X 10-12m

k = Boltzmans constant = 1.38 X 10-23 J/K

Other terms have usual meaning like pressure , temperature

Z = 1.414 X 3.14 X (270 X 10-12) 1/2 X 1776.3X 6 X 101325 / 1.38 X 10-23 X 298 = 8.5 X 1010 s-1

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