Question

A platinum ring is dropped in a pool of water and cools to equilibrium. Determine the initial temperature of the platinum ring (mass=366g) if the ring has a final temperature of 12.0 degrees celcius and loses 3.31kJ of heat. The specific heat capacity of platinum is 0.139J/gK

Answer 1

Heatv lost by ring is given by

m = 366 g

T_f = 12

s = 0.139

q = 3.31 kJ = 3310 J

Substituting , we get

T₀ - T_f = q/(ms) = 3310/(366*0.139) = 65.0627

Thus,

T₀ = T_f +  65.0627

= 12 +  65.0627

= 77.06 degrees celsius

Initial temperature = 77.06 degrees celsius