Question

The specific heat of a certain type of cooking oil is 1.75 J/(g·°C). How much heat energy is needed to raise the temperature of 2.62 kg of this oil from 23 °C to 191 °C?

Answer 1

mass = 2.62 kg = 2.62 x 10^3 g

temperature differece = 191 - 23 = 168°C

specific heat = 1.75 J/g·°C

heat energy Q = m Cp dT

                        = 2.62 x 10^3 x 1.75 x 168

                        = 770280 J

                        = 770 kJ