Question

Consider the reaction X ---> Y in a cell at 37 degrees Celcius. At equilibrium, the...

Consider the reaction X ---> Y in a cell at 37 degrees Celcius. At equilibrium, the concentrations of X and Y are 50 micrometers and 5 micrometers, respectively. Use this information and your knowledge of the relationships between deltaG, and deltaGo , and the equilibrium constant (K) to answer questions a-c.

a) What is the value of K for this reaction?

b) What is the value of the standard free energy? is the reaction X-->Y and energetically favorable or unfavorable reaction under standard conditions?

c) Imagine circumstances in which the concentration of X is 1000 micrometers and that of Y is 1 micrometer. Is conversion of X to Y favorable? Will it happen quickly?

Homework Answers

Answer #1

a) What is the value of K for this reaction?

equilibrium constant K = [Y] / [X] = 5 / 50 = 0.1

b)

deltaGo = - R T ln K

             = - 8.314 x 10^-3 x 310 x ln 0.1

             = 5.93 kJ

the reaction X-->Y is unfavorable reaction under standard conditions. because delta Go is positive.

(c)

equilibrium constant K = [Y] / [X] = 1 / 1000 = 0.001

no. it is unfavourable. because K value is less than 1

                          

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculating equilibrium concentrations when the net reaction proceeds forward Consider mixture B, which will cause the...
Calculating equilibrium concentrations when the net reaction proceeds forward Consider mixture B, which will cause the net reaction to proceed forward. Concentration (M)initial:change:equilibrium:[XY]0.500−x0.500−xnet→⇌[X]0.100+x0.100+x+[Y]0.100+x0.100+x The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced. Part B Based on a Kc value of 0.130 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Calculating equilibrium concentrations when...
Consider mixture B, which will cause the net reaction to proceed forward. Concentration (M)initial:change:equilibrium:[XY]0.500−x0.500−xnet→⇌[X]0.100+x0.100+x+[Y]0.100+x0.100+x The change...
Consider mixture B, which will cause the net reaction to proceed forward. Concentration (M)initial:change:equilibrium:[XY]0.500−x0.500−xnet→⇌[X]0.100+x0.100+x+[Y]0.100+x0.100+x The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced. A) Based on a Kc value of 0.210 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration...
Consider mixture B, which will cause the net reaction to proceed forward. Concentration (M)initial:change:equilibrium:[XY](0.500) (−x) (0.500−x)...
Consider mixture B, which will cause the net reaction to proceed forward. Concentration (M)initial:change:equilibrium:[XY](0.500) (−x) (0.500−x) net→⇌[X](0.100) (+x) (0.100+x) +[Y](0.100) (+x) (0.100+x) The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced. Part B Based on a Kc value of 0.130 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Consider mixture C, which will...