1.) Which transition in a hydrogen atom would emit the photon of greatest frequency?
n = 35 to n = 2
n= 6 to n = 2
n = 12 to n = 6
n = 1 to n = 4
n = 2 to n = 9
n = 3 to n = 1
***NOT n=35 to n=2***
2.) Which transition in a hydrogen atom would absorb the photon of greatest frequency?
n = 3 to n = 1
n = 6 to n = 2
n = 2 to n = 9
n = 35 to n = 2
n = 12 to n = 6
n = 1 to n = 4
***NOT n=2 to n=9***
3.) One is a "cation" with a 1+ charge, and the other is an "anion" with a 1- charge. The dashed line in the center represents the path of an uncharged particle.
What is the approximate ratio of the mass of B to the mass of A (the B/A ratio)? Express your answer as number (like 3.8 or 0.79), not as a fraction (like 7/6 or 7:6). (Hint : Can you tell which particle is heavier?)
4.)What are the frequency and energy of a photon with a wavelength of 527 nm?
frequency=
energy=
5.) Which of the following points could be concluded or
determined from Thomson's cathode ray experiment?
Check all the boxes that apply. (There may be anywhere from zero to
five correct statements.) This question is graded "all or nothing",
no partial credit.
-cathode rays were negatively charged
-cathode rays were particles, not light waves
-the numerical mass of the cathode rays
-the numerical charge of the cathode rays
-the charge to mass ratio of the cathode rays
6.) Rank the following charge/distance combinations from lowest energy to highest energy. Your answer should be a four letter "word" made up of the letters a, b, c and d. For example, if you think the order is a (lowest energy), then b, then c, then d (highest energy), you should enter the "word" abcd in the answer box. Note, the word has no spaces or commas.
a) A +2 charge and a -2 charge separated by 3 units of
distance
b) A -3 charge and a -1 charge separated by 3 units of
distance
c) A +1 charge and a +1 charge separated by 2 units of
distance
d) A -1 charge and a +2 charge separated by 3 units of distance
****NOT cdba****
7.) Determine the energy of an electron in the given quantum level of each of the following ions. (Hint: Each of the ions has a different number of protons, but each has only one electron, so the Bohr model applies.)
(a) Li2+ with n = 2
(b) O7+ with n = 6
1) In case of emission the quantum number of final orbit will be lesser than that of inital orbit (ni > nf)
The correct option is n=3 to n=1
E = hv
v = E/h = RH/h (1/ni2 - 1/nf2)
v comes out to highest in case of ni = 3 anf nf = 1
2) The energy of photon is directly proportional to energy (E = hv)
For absorption to take place , quantum number of initial orbit should be less than final (nf > ni)
Therefore the correct option is n =1 to n =4
v = E/h = RH/h (1/ni2 - 1/nf2)
v comes out to highest in case of ni =1 anf nf = 4
Get Answers For Free
Most questions answered within 1 hours.