Question

Calculate the final temp of a mixture of 140.0 g of ice initially at -21.5 C and 429.5g of water initially at 82.5.

Answer 1

Given that

mass of Ice = 140.0 g

mass of water = 429.5 g

Given that 140.0 g of ice initially at -21.5 C and 429.5g of water initially at 82.5 are mixed.

Therefore,

Heat lost by water at 82.5 °C = Heat gained by ice at -21.5 °C

Heat loss or gain Q = mcdT , c= specific heat of water

Let T be the final temperature

Hence,

429.5 g x c x [ 82.5 - T ] = 140.0 g x c x [T-(-21.5)]

35433.75 - 429.5 T = 140 T + 3010

140 T + 429.5 T = 35433.75 - 3010

569.5 T = 32423.75

T = 32423.75/569.5

= 56.93 ^oC

T = 56.93 ^oC

Therefore, final temperature of the mixture = 56.93 ^oC