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For the uncoupled and coupled reactions glucose + phosphate → glucose-6-phosphate, ΔG°' = +13.8 kJ/mol glucose...

For the uncoupled and coupled reactions glucose + phosphate → glucose-6-phosphate, ΔG°' = +13.8 kJ/mol glucose + ATP → glucose-6-phosphate + ADP, ΔG°' = -16.7 kJ/mol By how much does coupling to ATP increase the apparent equilibrium constant for the formation of glucose-6-phosphate? Given R = 8.315 J/mol · K. T = 298 K.

a) 1.2 times
b) 2.2 × 105 times
c) 2.2 × 108 times
d) 4.5 × 10-6 times
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Homework Answers

Answer #1

G = -RTlnKc

G = 13.8Kj/mole   = 13800joule/mole

13800 = -8.314*298lnKc

13800 = -2477.572knKc

-5.57   = lnKc

Kc1 = 0.0038

G = -RTlnKc

G = -16.7kj/mole   = -16700kj/mole

R = 8.314 joule/mole-K

T = 298K

-16700 = -8.314*298lnKc

-16700/2477.572 = lnKc

-6.74               = lnKc

Kc 2                      = 102.92 =831.7

Kc2/Kc1                  = 831.7/0.0038    = 2.2*105 times

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