If you have 120. mL of a 0.10 M TES buffer at pH 7.55 and you add 2.00 mL of 1.0 M HCl, what will be the new pH? (The pKa of TES is 7.55.)
Solution.
The formula of TES is:
The nitrogen of this compound can be protonated, TES is a weak base:
The pH can be found using Henderson-Hasselbach Equation:
The initial concentration is [TES]0 = [TES] + [TES(H+)];
The total volume of a mixture is 0.120 + 0.002 = 0.122 L.
The amount of the protonated form is equal to the amount of HCl added:
n(TES(H+)) = n(HCl) = c(HCl)V(HCl) = 1.0*0.002 = 0.002 mol.
n0(TES) = 0.1*0.120 = 0.012 mol.
[TES]0 = 0.012/0.122 = 0.098 M;
[TES(H+)] = 0.002/0.122= 0.016 M;
[TES] = 0.098-0.016 = 0.082 M;
Answer: 8.26.
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