Question

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.50 g of sodium carbonate is mixed with one containing 4.75 g of silver nitrate. How many grams of each of the following compounds are present after the reaction is complete? A) sodium carbonate B) sodium nitrate

Answer 1

Na2CO3 + 2AgNO3 = Ag2CO3 + 2NaNO3

m = 3.5 g of Na2CO3

m = 4.75 g of AgNO3

a)

grams present after reaction is complete

Na2CO3 = mass/MW = 3.5 /105.9888 = 0.03302235707

Ag2CO3 = mass/MW = 4.75 /275.7453 = 0.01722604156

ratio is1:2

0.03302235707 needs 0.03302235707*2 = 0.06604471414 which we do not have, so Ag2CO3 is limiting

expect 0 mols/grams of Ag2CO3 left

then

0.01722604156*1/2 = 0.00861302078 mol of Na2CO3 reacts

left =0.03302235707- 0.00861302078 = 0.02440933629mol are left

mass = mol*MW = 0.00861302078 *105.9888 = 0.91288373684 g left of Na2CO3